Question
Download Solution PDFसमीकरण ax2 + x + b = 0 चे मूळ समान असल्यास
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
दिलेले समीकरण ax2 + x + b = 0 आहे
वापरलेली संकल्पना:
चतुर्भुज समीकरणाचे सामान्य स्वरूप ax2 + x + b = 0 आहे
मूळांकरिता अट,
समान आणि वास्तविक मुळांसाठी, b2 – 4ac = 0
असमान आणि वास्तविक मुळांसाठी, b2 – 4ac > 0
काल्पनिक मुळांसाठी, b2 – 4ac
गणना:
समान आणि वास्तविक मुळांसाठी, b2 – 4ac = 0
⇒ b2 = 4ac
चतुर्भुज समीकरणाच्या सामान्य स्वरूपाशी तुलना केल्यानंतर आपल्याला मिळेल
b = 1, a = a आणि c = b
नंतर, b2 = 4ac
⇒ 1 = 4ab
⇒ ab = 1/4
∴ योग्य संबंध ab = 1/4 आहे
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