Question
Download Solution PDFजर एका चेंडूचे वस्तुमान आणि वेग दोन्ही दुप्पट केले तर गतिज ऊर्जा ______ पट होते.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
गतिज ऊर्जा:
- एखाद्या वस्तूच्या हालचालीमुळे प्राप्त होणाऱ्या ऊर्जेला गतिज ऊर्जा म्हणतात.
- सूत्र, गतिज ऊर्जा, \(K.E=\frac{1}{2}mv^2\) जिथे m = वस्तुमान, v = वेग
- गतिज ऊर्जेचे SI एकक ज्युल्स (J) आहे..
गणना:
दिलेले आहे:
गतिज ऊर्जा आहे, \(E=\frac{1}{2}mv^2\). . . . . . . . .(1)
जर m' = 2m, v' = 2v
नवीन गतिज ऊर्जा, \(K.E'=\frac{1}{2}m'v'^2\)
\(K.E'=\frac{1}{2}(2m)(2v)^2\)
\(K.E'=8\frac{1}{2}mv^2\)
समीकरण (1) वरून, K.E' = 8 K.E
त्यामुळे, गतिज ऊर्जा 8 पट होते.
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