Question
Download Solution PDF220 V, 100 W चा बल्ब 110 V स्त्रोताशी जोडलेला आहे. बल्बद्वारे वापरल्या जाणाऱ्या शक्तीची गणना करा.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
- विद्युत ऊर्जा: ज्या दराने विद्युत ऊर्जेचा उर्जेच्या इतर प्रकारांमध्ये अपघटन होतो त्याला विद्युत उर्जा म्हणतात. म्हणून,
\(P = \frac{W}{t} = VI = {I^2}R = \frac{{{V^2}}}{R}\)
जेथे V = विभवांतर, R = विद्युतरोध आणि I = विद्युतधारा.
गणना:
दिलेल्याप्रमाणे - विभवांतर (V) = 220 V, बल्बची शक्ती (P) = 100 W आणि प्रत्यक्ष व्होल्टता (V')= 110 V
- बल्बच्या विद्युतरोधाची गणना याप्रमाणे केली जाऊ शकते,
\(\Rightarrow R=\frac{V^2}{P}=\frac{(220)^2}{100}=484 \,\Omega\)
- बल्बद्वारे वापरली जाणारी शक्ती.
\(\Rightarrow P=\frac{V^2}{R}=\frac{(110)^2}{484}=25 \,W\)
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