Question
Download Solution PDFIn CE configuration, the collector supply voltage VCC = 10 v, and RC = 8 ΚΩ. Determine the Quiescent point Q for zero signal if the base current is IB = 15 μA and β = 40.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFQuiescent point
To determine the Quiescent point (Q), for zero signal in a Common Emitter (CE) configuration, we need to find the quiescent values of the collector's current (IC), emitter current (IE), and collector voltage (VCE).
\(I_C=\beta I_B\)
\(I_E=I_C+I_B\)
\(V_{CE}=V_{CC}-I_CR_C\)
Calculation
Given, VCC = 10 v, and RC = 8 ΚΩ
IB = 15 μA and β = 40
\(I_C=40\times 15\times 10^{-6}\)
\(I_C=0.6\space mA\)
\(V_{CE}=10-(0.6\times 8)\)
\(V_{CE}=5.2V\)
Last updated on May 29, 2025
-> SSC JE Electrical 2025 Notification will be released on June 30 for the post of Junior Engineer Electrical/ Electrical & Mechanical.
-> Applicants can fill out the SSC JE application form 2025 for Electrical Engineering from June 30 to July 21.
-> SSC JE EE 2025 paper 1 exam will be conducted from October 27 to 31.
-> Candidates with a degree/diploma in engineering are eligible for this post.
-> The selection process includes Paper I and Paper II online exams, followed by document verification.
-> Prepare for the exam using SSC JE EE Previous Year Papers.