Question
Download Solution PDFIf the radius of a circular current carrying coil is tripled, then the magnetic field at the centre of the coil becomes (all other factors remains same):
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The magnetic field at the center of the coil is given by:
\(B={μ \over 2}{I\over R}\)
where, B = Magnetic field density
μ = Permeability
I = Current
R = Radius
Explanation
From the above expression, the magnetic field is inversely proportional to the radius of the coil.
\(B\space \alpha \space {1\over R}\)
If the radius of a circular current-carrying coil is tripled, then the magnetic field at the center of the coil becomes one-third.
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