Question
Download Solution PDFIf the inverse of the matrix A =\(\begin{bmatrix}3 & 1 & 2 \\ 4&2 & 1\\ 2 & a & 1 \end{bmatrix}\)does not exist then the value of a is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Consider a matrix A and let its inverse be A-1
\(\rm {A^{ - 1}} = \frac{{{\rm{adj\;}}\left( {\rm{A}} \right){\rm{\;}}}}{{{\rm{det\;}}\left( {\rm{A}} \right)}}\)
Here; adj (A) is adjoint of matrix A and det (A) is determinant of matrix A.
⇒ If det (A) ≠ 0, so the inverse of a matrix exists.
⇒ If det (A) = 0, so inverse of a matrix does not exist.
Calculation:
Given A = \(\begin{bmatrix}3 & 1 & 2 \\ 4&2 & 1\\ 2 & a & 1 \end{bmatrix}\)
For A-1 does not exist the |A| = 0
|A| = \(\begin{vmatrix}3 & 1 & 2 \\ 4&2 & 1\\ 2 & a & 1 \end{vmatrix}\) = 0
|A| = 3(2 - a) - 1(4 - 2) + 2(4a - 4)
|A| = 6 - 3a - 2 + 8a - 8
|A| = 5a - 4
|A| = 0
5a - 4 = 0
∴ a = \(\frac 4 5\)
Last updated on May 30, 2025
->UPSC has released UPSC NDA 2 Notification on 28th May 2025 announcing the NDA 2 vacancies.
-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.
->The NDA exam date 2025 has been announced for cycle 2. The written examination will be held on 14th September 2025.
-> Earlier, the UPSC NDA 1 Exam Result has been released on the official website.
-> The selection process for the NDA exam includes a Written Exam and SSB Interview.
-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100.
-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential.