Question
Download Solution PDFHow is the e.m.f. generated within the armature of a d.c. generator represented?
This question was previously asked in
PGCIL DT Electrical 08 Feb, 2024 Shift 1 Official Paper
Answer (Detailed Solution Below)
Option 4 : Φ Z N (P/60A) volts
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CT 1: Classification I
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Detailed Solution
Download Solution PDFIn a dc generator, generated emf is given as
\(E = \frac{{ZP\phi N}}{{60\;A}}\)
E = V + Ia Ra
Where,
- Z is conductor per pole,
- P is the number of poles,
- Φ is the flux per pole,
- N is the speed in rpm,
- A is the number of parallel paths,
- Ia is armature current,
- Ra is armature resistance,
- V is terminal voltage
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