Question
Download Solution PDFयदि sin2 θ − 3 sin θ + 2 = 0 है, तो θ का मान (जहाँ 0° ≤ θ ≤ 90° है) ज्ञात कीजिए।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
sin2 θ − 3 sin θ + 2 = 0
प्रयुक्त अवधारणा:
1. -1 ≤ sin θ ≤ 1
2. sin 90° = 1
गणना:
sin2 θ − 3 sin θ + 2 = 0
⇒ sin2 θ − 2 sin θ - sin θ + 2 = 0
⇒ sin θ(sin θ - 2) - 1(sin θ - 2) = 0
⇒ (sin θ - 2) (sin θ - 1) = 0
इसलिए, sin θ = 1 (∵ sin θ ≠ 2)
⇒ sin θ = sin 90°
⇒ θ = 90°
∴ θ का मान 90° है।
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