Question
Download Solution PDF∠A, ∠B और ∠C एक त्रिभुज के तीन कोण हैं और ∠A/4 + ∠B/4 + ∠C/5 = 41°, तो ∠A + ∠B का मान ज्ञात कीजिए।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है,
∠A, ∠B और ∠C एक त्रिभुज के तीन कोण हैं।
∠A/4 + ∠B/4 + ∠C/5 = 41°
सूत्र:
त्रिभुज के तीनों कोणों का योग 180 ° होता है।
हल:
∠A/4 + ∠B/4 + ∠C/5 = 41°
⇒ (5∠A + 5∠B + 4∠C)/20 = 41°
⇒ (∠A + 4∠A + ∠B + 4∠B + 4∠C)/20 = 41°
⇒ (∠A + ∠B + 4∠A + 4∠B + 4∠C)/20 = 41°
⇒ ∠A + ∠B + 4(∠A + ∠B + ∠C) = 41° × 20
⇒ ∠A + ∠B + 4 × 180° = 820°
⇒ ∠A + ∠B = 820° - 720°
⇒ ∠A + ∠B = 100°
∴ ∠A + ∠B का मान 100° है l
Last updated on May 29, 2025
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