For what values of k is the system of equations 2k2x + 3y - 1 = 0, 7x - 2y + 3 = 0, 6kx + y + 1 = 0 consistent?

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  1. \(\rm \frac{3±\sqrt{11}}{10}\)
  2. \(\rm \frac{21±\sqrt{161}}{10}\)
  3. \(\rm \frac{3±\sqrt{7}}{10}\)
  4. \(\rm \frac{4±\sqrt{11}}{10}\)

Answer (Detailed Solution Below)

Option 2 : \(\rm \frac{21±\sqrt{161}}{10}\)
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Concept:

Consider three linear eqaution in two variable:

a1x + b1y + c1 = 0

a2x + b2y + c2 = 0

a3x + b3y + c3 = 0

Condition for the consistency of three simultaneous linear equations in 2 variables:

​​​​\( \left| {\begin{array}{*{20}{c}} a_1&b_1&c_1\\ a_2&b_2&c_2\\ a_3&b_3&c_3 \end{array}} \right|=0\)

Formula for Quadratic equation:

ax2 + bx + c = 0

x = \(\rm \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a}\)

Calculation:

2k2x + 3y - 1 = 0      ....(1)

7x - 2y + 3 = 0      ....(2)

6kx + y + 1 = 0      ....(3)

For consistency of given simultaneous equation,

\( \left| {\begin{array}{*{20}{c}} 2k^2&3&-1\\ 7&-2&3\\ 6k&1&1 \end{array}} \right|=0\)

⇒ 2k2(-2- 3) - 3(7 - 18k) - 1(7 + 12k) = 0

⇒ -10k2 - 21 + 54k - 7 - 12k = 0

⇒ -10k2 + 42k - 28 =  0

5k2 - 21k + 14 =  0

By using the formula,

\(x=\rm \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a}\)

\(\Rightarrow k=\rm \frac{-(-21) \pm \sqrt{(-21)^{2} - 4(5)(14)}}{2\times 5}\)

\(\therefore k=\rm \frac{21 \pm \sqrt{161}}{10}\)

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