Find the value of 'v0' in the following circuit.

F1 Koda Raju 12.4.21 Pallavi D10

This question was previously asked in
SSC JE EE Previous Paper 12 (Held on: 24 March 2021 Evening)
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  1. 12 V
  2. 96 V
  3. 48 V
  4. 24 V

Answer (Detailed Solution Below)

Option 3 : 48 V
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Detailed Solution

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Concept:

While applying KVL, the direction in which loop is to be traced is not important and following the sign convention is most important which is shown in below circuit

RRB JE EE 140 11Q Basic Concepts 2 - Final Hindi images Q10

We can write an equation by using KVL around this closed path as,

-I1 R1 + E1 – I2 R2 – I3 R3 – I4 R4 + E2 = 0 (Required KVL equation)

i.e. E1 + E = I R1 + I2R2 + I3R3 + I4R4

Explanation:

Circuit diagram:
F1 Koda Raju 12.4.21 Pallavi D14
Applying KVL in loop:

12 - 4 i - 2vo + 4 - 6 i = 0

\(i = \frac{12+4-2V_o}{10}.....(1)\)

Also,

\(i = -\frac{v_o}{6}.....(2)\) 

Substituting ' i ' from equation (2) into (1).

\(\frac{-v_o}{6}=\frac{16-2v_o}{10}\)

2 vo = 16 x 6

v0 = 48 V.

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