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কর্মচারীদের বয়সের মাঝারিভাবে প্রতিসম বণ্টনের জন্য, গড় = 20 এবং প্রচুরক = 25, মধ্যমানের আনুমানিক মান কত হবে?

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SSC CGL Tier-II ( JSO ) 2019 Official Paper ( Held On : 17 Nov 2020 )
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  1. \(21\dfrac{1}{3}\)
  2. \(21\dfrac{2}{3}\)
  3. \(22\dfrac{1}{3}\)
  4. \(22\dfrac{2}{3}\)

Answer (Detailed Solution Below)

Option 2 : \(21\dfrac{2}{3}\)
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Detailed Solution

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প্রদত্ত

গড় = 20

প্রচুরক = 25

অনুসৃত সূত্র

3 × মধ্যমান = প্রচুরক + 2 × গড়

গণনা

মধ্যমান = (প্রচুরক + 2 গড়)/3

⇒ (25 + 2 × 20)/3

⇒ (25 + 40)/3

⇒ 65/3

∴ মধ্যমান = 21 2/3
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Latest SSC CGL Updates

Last updated on Jun 13, 2025

-> The SSC CGL Notification 2025 has been released on 9th June 2025 on the official website at ssc.gov.in.

-> The SSC CGL exam registration process is now open and will continue till 4th July 2025, so candidates must fill out the SSC CGL Application Form 2025 before the deadline.

-> This year, the Staff Selection Commission (SSC) has announced approximately 14,582 vacancies for various Group B and C posts across government departments.

->  The SSC CGL Tier 1 exam is scheduled to take place from 13th to 30th August 2025.

->  Aspirants should visit ssc.gov.in 2025 regularly for updates and ensure timely submission of the CGL exam form.

-> Candidates can refer to the CGL syllabus for a better understanding of the exam structure and pattern.

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-> Attempt SSC CGL Free English Mock Test and SSC CGL Current Affairs Mock Test.

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