A random variable X has the distribution law as given below:

X

1

2

3

P(X = x)

0.3

0.4

0.3


The variance of the distribution is:

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  1. 0.4
  2. 0.6
  3. 0.2
  4. None of these

Answer (Detailed Solution Below)

Option 2 : 0.6
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Detailed Solution

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Concept:

For a random variable X = xi with probabilities P(X = x) = pi:

  • Mean/Expected Value: μ = ∑pixi.
  • Variance: Var(X) = σ2 = ∑pi(xi)2 - (∑pixi)2 = ∑pi(xi)2 - μ2.
  • Standard Deviation: σ = \(\rm \sqrt{Var(X)}\).

 

Calculation:

We have x1 = 1, x2 = 2, x3 = 3 and p1 = 0.3, p2 = 0.4, p3 = 0.3.

Now, ∑pixi = (0.3 × 1) + (0.4 × 2) +(0.3 × 3)

= 0.3 + 0.8 + 0.9

= 2

And, ∑pi(xi)2 = (0.3 × 12) + (0.4 × 22) +(0.3 × 32)

= 0.3 + 1.6 + 2.7

= 4.6

∴ Var(X) = σ2 = ∑pi(xi)2 - (∑pixi)2 = 4.6 - 22 = 4.6 - 4 = 0.6.

The variance of the distribution is Var(X) = 0.6.

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