Question
Download Solution PDFA pipe of internal diameter 'd' and thickness of wall 't', carries fluid with intensity of pressure 'p'. Hoop stresses in the wall will be:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
- Consider a thin pressure vessel having closed ends and contains fluid under a gauge pressure P. Then the walls of the cylinder will have longitudinal stress, circumferential stress and radial stress.
- As shown in the figure, a point of the shell having stresses from all sides i.e. tri-axial stresses.
- σL = longitudinal stress (tensile), σr = radial stress (compressive), σh = circumferential stress (tensile).
As, σr <<<< σL and σh, therefore we neglect σr and assumed the bi-axial stresses.
Circumferential or hoop stress: \({σ _h} = \frac{{Pd}}{{2t}}\)
Longitudinal or axial stress: \({σ _L} = \frac{{Pd}}{{4t}}\)
where d is the internal diameter and t is the wall thickness of the cylinder.
- For the spherical shell, longitudinal stress and circumferential stress both are equal,
σh = σL = \(\frac{Pd}{4t}\)
Last updated on May 28, 2025
-> SSC JE notification 2025 for Civil Engineering will be released on June 30.
-> Candidates can fill the SSC JE CE application from June 30 to July 21.
-> The selection process of the candidates for the SSC Junior Engineer post consists of Paper I, Paper II, Document Verification, and Medical Examination.
-> Candidates who will get selected will get a salary range between Rs. 35,400/- to Rs. 1,12,400/-.
-> Candidates must refer to the SSC JE Previous Year Papers and SSC JE Civil Mock Test, SSC JE Electrical Mock Test, and SSC JE Mechanical Mock Test to understand the type of questions coming in the examination.
-> The Staff Selection Commission conducts the SSC JE exam to recruit Junior Engineers in different disciplines under various departments of the Central Government.