Question
Download Solution PDFA gear having 100 teeth is fixed and another gear having 25 teeth revolves around it, the centre lines of both gears being joined by an arm. How many revolution will be made by gear of 25 teeth for one revolution of arm:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Calculation:
Given:
TB = 100; TA = 25
|
Step No. |
Conditions of motion |
Revolutions of elements |
||
|
Arm C |
Gear A |
Gear B |
||
|
1.
2.
3.
4. |
Arm fixed-gear A rotates though + 1 revolution (i.e. 1 rev. anticlockwise) Arm fixed-gear A rotates through + x revolutions Add + y revolutions to all elements
Total motion |
0
0
+y
+y |
+ 1
+x
+y
x + y |
\(- \frac{{{T_A}}}{{{T_B}}}\)
\(- x \times \frac{{{T_A}}}{{{T_B}}}\)
+y
\(y - x \times \frac{{{T_A}}}{{{T_B}}}\) |
y = 1; NB = 0
\(\begin{array}{l} {N_B} = y - x \times \frac{{{T_A}}}{{{T_B}}} = 1 - x \times \frac{{25}}{{100}} = 1 - \frac{x}{4} = 0 \Rightarrow x = 4\\ {N_A} = x + y = 4 + 1 = 5 \end{array}\)
Last updated on Mar 27, 2025
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