A constant voltage of 50 V is maintained between the points A and B of the circuit shown in the figure. The current through the branch CD of the circuit is:

Question

Question

This question was previously asked in

NEET 2025 Official Paper (Held On: 04 May, 2025)

Answer 1

Correct option is: (2) 2.0 A

1 (8)

R_AB = (1Ω / 3Ω) in series with (2Ω / 4Ω)

⇒ (1 × 3) / (1 + 3) + (2 × 4) / (2 + 4)

= 3 / 4 + 8 / 6 = (9 + 16) / 12 = 25 / 12 Ω

Now total current through the cell

I = 50 / (25 / 12) = 24 A

I_1Ω = (3 / 4) × 24 = 18 A, I_3Ω = (1 / 4) × 24 = 6 A

I_2Ω = (4 / 6) × 24 = 16 A, I_4Ω = (2 / 6) × 24 = 8 A

Using junction rule at C,

I_CD = 18 − 16 = 2 A (from C to D)