Question
Download Solution PDFA 10-litre bucket of water is lifted by a distance of 10 m with the help of a pulley on the moon. Calculate the work done on the bucket, ignoring the mass of the bucket itself, in terms of gmoon, the acceleration due to gravity on the moon.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe correct answer is 100 gmoon.
Key Points
- The work done is calculated using the formula W = m × g × h, where m is the mass of the object, g is the acceleration due to gravity, and h is the height lifted.
- The mass of the water is 10 kg since 1 litre of water has a mass of 1 kg.
- On the moon, the acceleration due to gravity is denoted as gmoon.
- Substituting the values into the formula: W = 10 × gmoon × 10 = 100 gmoon.
- The correct answer is therefore 100 gmoon, which matches option 1.
Additional Information
- Work (W):
- Work is defined as the product of force applied and the displacement in the direction of the force.
- Its SI unit is the joule (J).
- Acceleration due to gravity on the moon (gmoon):
- The moon's gravity is approximately 1/6th of Earth's gravity.
- The value of gmoon ≈ 1.63 m/s2.
- Mass and weight:
- Mass is a measure of the amount of matter in an object (measured in kg).
- Weight is the force exerted by gravity on an object and is calculated as W = m × g.
- Pulley systems:
- Pulleys are used to lift heavy objects by reducing the amount of force required.
- In this problem, the pulley system aids in lifting the bucket vertically upward against gravity.
Last updated on Apr 24, 2025
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