Question
Download Solution PDFΘ1 and θ2 are the angels of elevation from ‘A’ to the top and bottom of a vertically held rod of length ‘S’ at B. The horizontal distance AB will be
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFLet the horizontal distancebetween A and B be ‘d’.
In ΔABD,
\({\rm{tan}}{{\rm{\theta }}_2} = \frac{{\rm{h}}}{{\rm{d}}}\)
Again,
In ΔACD,
\({\rm{tan}}{{\rm{\theta }}_1} = \frac{{{\rm{h}} + {\rm{s}}}}{{\rm{d}}}\)
Solving both the equation we get,
\({\bf{d}} = \frac{{\bf{s}}}{{\tan {{\bf{\theta }}_1} - \tan {{\bf{\theta }}_2}}}\)
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